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I'll ask someone tomorrow for you.
Tried to type in here, but can't make the superscript, so a screenshot:
... I think ... it's been 35 years at least
PS Sorry, should've included the formula: (a+bi)(c+di) = (ac−bd) + (ad+bc)i
And now this brings to mind Moivres theorem and I can't sleep.GLK said:Tried to type in here, but can't make the superscript, so a screenshot: ... I think ... it's been 35 years at least PS Sorry, should've included the formula: (a+bi)(c+di) = (ac−bd) + (ad+bc)i
Tried to type in here, but can't make the superscript, so a screenshot:
... I think ... it's been 35 years at least
PS Sorry, should've included the formula: (a+bi)(c+di) = (ac−bd) + (ad+bc)i
... What application would this stuff have in the real world?....
What application would this stuff have in the real world?
The only imaginary number I can bring to mind is the number of glasses of vin rouge I tell my wife I enjoyed before bed.
What application would this stuff have in the real world? Serious question.
Thanks GLK! This looks correct (to my untrained eye). Will check with her tomorrow....
First off, electrical engineers like me use "j" because "i" is almost always used to mean "current" in our equations. Where most people would write "a + bi", we'd write "a + bj", but it means the same thing.Druk said:I'm usually struggling with my Tesco bill. What application would this stuff have in the real world? Serious question.
First off, electrical engineers like me use "j" because "i" is almost always used to mean "current" in our equations. Where most people would write "a + bi", we'd write "a + bj", but it means the same thing.
Electrical engineers often have to solve "differential equations" (remember them), which are a bit hard to explain without delving into calculus. Basically, a differential equation relates functions to their rates of growth. The solution to a differential equation is usually a function, not a number. As a specific example (keeping away from electrical engineering), suppose you have a snowplow that keeps piling up more and more snow in front of it so that the further it goes, the heavier the load it is pushing, and the heavier the load, the slower it goes, and the slower it goes the slower the pile of snow in front of it grows. You can (with a differential equation) relate the amount of snow at a given time t [call it A(t)] to the velocity of the plow, and the equations can be solved to give the function A(t) at all times t. But often, it's easier to solve differential equations in the domain of complex numbers because the equations are a lot nicer, but you know that the solution you care about is just the real part of the solution.
Sorry, that was making sense as I wrote it, but now that I read it with an imaginary new hat on, it'a not great as an answer. So I'll just have to say that there are uses for complex numbers in some fields, just not those filled with potatoes for Tesco.
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